Making the variable zero before going to the called function

I have one complex problem, for me it is very complex.

I need to make a variable zero inside the if statements. but here if statements is a called function which contains three input arguments(Area, width, Diameter).

code like this:

% A is ara matrix
% D is diamter matrix
% W is width matrix.
Function L = Area_1(A, W,D)
if W == 0
L = .........
else 
L = ......
end
end
Function L_A = Leitwert
[A,W,D] = Matrix_1;
% width matrix is like this W = [10 20 30 0];
% Diameter matrix is like this D = [ 5 5 5 0];
for i = 1:size(A,1)
for j = 1:size(A,2)
if M_1 == metal  &&  M_2 == metal
L_A = Area_1(a,w,d);
elseif M_1 == metal && M_2 == air
L_B = .......
end
end
end
% The problem is how to make width zero inside the if statements even though it is a value.

For an example: i = 1, j = 1;

width = 10 Diameter = 5;

L_A(1,1) = ........ % (here second equation is sloved in the function Area_1 to give L_A)

Now I want L_A(1,2) now

but L_A (1,2) should be from the first equation of the function Area_1 even though Width(W) is a value.

Why? I can't make W(1,2) = 0 since L_B needs that width value if the condition is metal and air..

If the question is not clear still, kindly ask!

any suggestions and answered will be most welcomed!

[Jan]

The pseudo-code is not clear, but confusing. Please use standard Matlab syntax and post working code.

What is "Matrix_1"? Where do M1 and M2 come from? In

L_A = Area_1(a,w,d);

a, w, d are undefined. width does not occur anywhere, so what is the point of "make width zero"?

[surendra kumar Aralapura mariyappa]

Okay,

I have four materials 1,2,3,4.

1,2,3 are three materials and 4 is air

1 and 4 are in series and 2 and 4 are in parallel 3 and 4 are in series,

1 and 2 in series, 2 and 3 in series

A is area matrix (4,4)

% D is diameter matrix (1,4)

% W is width matrix.(1,4)

Function L = Area_1(a, w,d)
% a = area
% w = width
% d = diameter
if w == 0
L =   a * d % when material and air  are in series 
else 
L = a*d*w     % when material and air  are in parallel
end
Function L = Area_2(a, w,d)

L = a*d*w     % when material and material   are in parallel %and in series

end
Function L_A = Leitwert
[A,W,D] = Matrix_1;
% width matrix is like this W = [10 20 30 0];
% Diameter matrix is like this D = [ 5 5 5 0];
% Area matrix is like this A = [ 0 47 0 23; 47 0 47 18; 0 47 0 23; 23 18 23 %0];
for i = 1:size(A,1)
for j = 1:size(A,2)
M_1 = Material(i);     % called function to check whether i and j material %or air
M_2 = Material(j);
if M_1 == metal  &&  M_2 == metal
L_A = Area_2( A(i,j),W(i),d(i));
disp(L_A);
elseif M_1 == metal && M_2 == air
L_B = Area_1(A(i,j),W(i),d(i));
disp(L_B);
elseif M_1 == air && M_2 == metal
L_B = 100;
end
end
end

Now the problem is when the i = material and j = air, L_B(1,4) or L_B(3,4) or L_B(2,4) slover goes to L_B = Area_1 (); when the slover goes into this function, always A(i,j), D(i) and W(i) will have the values, L_B will give the parallel equation solved value since W(i) will not be zero.

So here How to make W(i) is zero when the Material and air in series and L_B should be value of computed series equation, which menas L_B(1,4) or L_B(3,4) W(i) should be zero. Here we can't simple write if L_B(1,4) or L(3,4) which menas i == 1 && j== 4, W(i) == 0;

As I said earlier, the connection can be changed, may be for other model, 1 and 4 are in parallel, 4 may be material and 5 may be air then L_B(1,4) becomes L(1,5) in parallel.

Since code should be general, I can't make any changes in the Input matrices, because connection will be changed for the other models.

Here solver should know this is in series W(i) should be zero , when in parallel W(i) should not be zero.

I think this expplanation is enough.

if you have any suggestions, most welcomed.

[Jan]

I've formatted the text as text and the Matlab code as code to improve the readability. If you write "function" with lower case characters and apply a standard indentation (press Ctrl-a Ctrl-i in the editor), the code would be even nicer.

"when the i = material and j = air, L_B(1,4) or L_B(3,4) or L_B(2,4) slover goes to L_B = Area_1 ()" - I do not understand, what this means. L_B is set by L_B = Area_1, which replies a scalar. Then there is no L_B(1,4) or L_B(3, 4). I do not understand which "solver" is "going" to where.

Sorry, I do not get an idea of what you try to do.

Answer 1

[James Browne]

Greetings,

I think I understand what your problem is and I think I may have a solution for you. Perhaps you should use a different variable in the function Area_1 to decide which equation to use, call it "eq" or something (name does not really matter, obviously). Then in the function Area_1 would look something like:

function L = Area_1(a, w,d)
% a = area
% w = width
% d = diameter
if eq == 0
L =   a * d % when material and air  are in series 
else 
L = a*d*w     % when material and air  are in parallel
end

Then all you have to do is set the variable "eq" to zero when it is appropriate to use equation 1 and set "eq" to 1 (or some other value other than zero) when it is appropriate to use equation 2. I do not really see a reason to use the variable "w" in the if statement which decides which equation to use, but maybe I am missing something?

If you do need to use "w" to decide which equation to use, you can always store the current value of "w" in a different variable, say "x", for example, then set "w" to zero to select the correct equation in the Area_1 function, once the Area_1 function completes its task, use the value stored in "x" to reset the current value of "w" to its original value. I can't quite tell from your code when materials are in seriese or parallel so I can't write the logic staement for you but if you wanted to be able to set "w" to zero and then reset it, it could be done in a way similar to the following code:

if ('logic statement for "w" needs to be zero')
x = w(i);
w(i) = 0;
L_A = Area_2( A(i,j),W(i),d(i));
w(i) = x;
end

I hope this at least points you in the right direction~