Need help creating a for loop
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Hello.
I need to create a loop that can do the following:
I have to create a distance matrix for plotting my graph. The total distance is 95 m with 5 m spaces. So it needs to start at 5 and end at 95. Start from 5 again till 90 and start from 5 till 85. 5 till 80 and so on.
It should look like this:
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 5 10 15 20 25 30 35 40 45 50 55 60 65 70 5 10 15 20 25 30 35 40 45 50 55 60 65 5 10 15 20 25 30 35 40 45 50 55 60 5 10 15 20 25 30 35 40 45 50 555 10 15 20 25 30 35 40 45 50 5 10 15 20 25 30 35 40 45 5 10 15 20 25 30 35 40 5 10 15 20 25 30 355 10 15 20 25 30 5 10 15 20 25 5 10 15 20 5 10 15 5 10 5
2 commentaires
Prasanth Sikakollu
le 18 Juin 2019
Is this the one you are looking for?
A =
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 0
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 0 0
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 0 0 0
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 0 0 0 0
5 10 15 20 25 30 35 40 45 50 55 60 65 70 0 0 0 0 0
5 10 15 20 25 30 35 40 45 50 55 60 65 0 0 0 0 0 0
5 10 15 20 25 30 35 40 45 50 55 60 0 0 0 0 0 0 0
5 10 15 20 25 30 35 40 45 50 55 0 0 0 0 0 0 0 0
5 10 15 20 25 30 35 40 45 50 0 0 0 0 0 0 0 0 0
5 10 15 20 25 30 35 40 45 0 0 0 0 0 0 0 0 0 0
5 10 15 20 25 30 35 40 0 0 0 0 0 0 0 0 0 0 0
5 10 15 20 25 30 35 0 0 0 0 0 0 0 0 0 0 0 0
5 10 15 20 25 30 0 0 0 0 0 0 0 0 0 0 0 0 0
5 10 15 20 25 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 10 15 20 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 10 15 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 10 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Réponse acceptée
Guillaume
le 18 Juin 2019
No need for a loop:
result = nonzeros(flipud(tril(repmat((95:-5:5)', 1, 95/5))))'
Of course, if this is homework and you do need to use a loop, then we won't give you the solution but can tell you where you're going wrong if you show what you've done.
Plus de réponses (2)
vidhathri bhat
le 18 Juin 2019
Hi
You can just use simple for loops to do this.
data = []
for i=95:-5:5
data = [data 5:5:i]
end
end
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