Need help creating a for loop
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Hello.
I need to create a loop that can do the following:
I have to create a distance matrix for plotting my graph. The total distance is 95 m with 5 m spaces. So it needs to start at 5 and end at 95. Start from 5 again till 90 and start from 5 till 85. 5 till 80 and so on.
It should look like this:
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 5 10 15 20 25 30 35 40 45 50 55 60 65 70 5 10 15 20 25 30 35 40 45 50 55 60 65 5 10 15 20 25 30 35 40 45 50 55 60 5 10 15 20 25 30 35 40 45 50 555 10 15 20 25 30 35 40 45 50 5 10 15 20 25 30 35 40 45 5 10 15 20 25 30 35 40 5 10 15 20 25 30 355 10 15 20 25 30 5 10 15 20 25 5 10 15 20 5 10 15 5 10 5
2 commentaires
Prasanth Sikakollu
le 18 Juin 2019
Is this the one you are looking for?
A =
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 0
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 0 0
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 0 0 0
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 0 0 0 0
5 10 15 20 25 30 35 40 45 50 55 60 65 70 0 0 0 0 0
5 10 15 20 25 30 35 40 45 50 55 60 65 0 0 0 0 0 0
5 10 15 20 25 30 35 40 45 50 55 60 0 0 0 0 0 0 0
5 10 15 20 25 30 35 40 45 50 55 0 0 0 0 0 0 0 0
5 10 15 20 25 30 35 40 45 50 0 0 0 0 0 0 0 0 0
5 10 15 20 25 30 35 40 45 0 0 0 0 0 0 0 0 0 0
5 10 15 20 25 30 35 40 0 0 0 0 0 0 0 0 0 0 0
5 10 15 20 25 30 35 0 0 0 0 0 0 0 0 0 0 0 0
5 10 15 20 25 30 0 0 0 0 0 0 0 0 0 0 0 0 0
5 10 15 20 25 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 10 15 20 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 10 15 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 10 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Tee-Kay
le 18 Juin 2019
Réponse acceptée
Plus de réponses (2)
vidhathri bhat
le 18 Juin 2019
Hi
You can just use simple for loops to do this.
data = []
for i=95:-5:5
data = [data 5:5:i]
end
end
1 commentaire
Tee-Kay
le 18 Juin 2019
v = nonzeros((5:5:95).' .* fliplr(triu(ones(19)))).'
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