Is there a method to linear index to a transpose matrix without taking the transpose?
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Douglas Farinelli
le 18 Juin 2019
Commenté : Douglas Farinelli
le 19 Juin 2019
Is there a method to linear index to a transpose matrix without taking the transpose?
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Image Analyst
le 19 Juin 2019
What code is that? Where did you attach it? Who wrote it?
And what is wrong with using the transpose operator '? Why do you need a different way?
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Douglas Farinelli
le 18 Juin 2019
2 commentaires
Walter Roberson
le 18 Juin 2019
Yes.
Note: for a 2D matrix, ind2sub is (column_number - 1) * number_of_rows + row_number .
You can therefore optimize the access (row_number, column_number) to the transpose (column_number, row_number) as
(row_number - 1) * number_of_rows + column_number
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