Plotting inverse laplace w.r.t.

4 vues (au cours des 30 derniers jours)
Yash Kulkarni
Yash Kulkarni le 21 Juin 2019
Commenté : Vishnu Vardhan le 21 Juin 2019
How can I plot inverse laplace of a fucntion which contains exponential and hyperbolic functions on Matlab? like
(0.2696)/(s-0.1384*(s^1)*((exp(1.2468*s)+exp(-1.2468*s))/((exp(1.2468*s)-exp(-1.2468*s)))))

Réponses (1)

Vishnu Vardhan
Vishnu Vardhan le 21 Juin 2019
Hi Yash
You can use ilaplace function to compute the inverse laplace of H as shown below.
h=matlabFunction(ilaplace(H));
t=1:0.01:100;
plot(t,h(t))
  2 commentaires
Yash Kulkarni
Yash Kulkarni le 21 Juin 2019
Hi Vishnu,
ilaplace wroks only for simple functions. In this case it throws back to me the orginal function.
Vishnu Vardhan
Vishnu Vardhan le 21 Juin 2019
From the documentation page it looks like the inputs can be symbolic expression | symbolic function | symbolic vector | symbolic matrix and also given that if it cannot compute the inverse then it returns an unevaluated call to ilaplace.Hence you are observing that results.

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