I am looking to express a parametrized vector function and draw the surface..

2 commentaires

Adam Danz
Adam Danz le 23 Juin 2019
How can we help you with that? Where are you stuck?
Thomas Starai
Thomas Starai le 23 Juin 2019
What is the syntax for something like:
x(u,v) = ( 2-v*sin(u/2)*sin(u), 2-v*sin(u/2)*cos(u), v*cos(u/2) )
?

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 Réponse acceptée

Star Strider
Star Strider le 24 Juin 2019

0 votes

You pretty much wrote it yourself:
x = @(u,v) [2-v.*sin(u/2).*sin(u); 2-v.*sin(u/2).*cos(u); v.*cos(u/2)];
See the documentation sections on Anonymous Functions (link) and Vectorization (link) for an extended discussion of both. The documentation for the ndgrid (link) function will also be helpful.

4 commentaires

Thomas Starai
Thomas Starai le 24 Juin 2019
can I create this function using the smbolic math toolbox?
Star Strider
Star Strider le 24 Juin 2019
You could, however that is going to be slower and less efficient than using the anonymous function implementation.
The Symbolic Math Toolbox is best for derivations and such that are done once, then using the matlabFunction function, implemented iin base MATLAB, taking advantage of its computational efficiencies.
Thomas Starai
Thomas Starai le 24 Juin 2019
Symbolic math is intriging.....efficiency is not an issue.
After looking at anonymous functions, I fail to see why you couldn't just define a function without the @ operator. Can you provided some insigh as to why this is necessary?
Star Strider
Star Strider le 24 Juin 2019
The @ operator denotes a function handle, and is necessary if you want to define it as an anonymous function. You could define it as a function file, however that is usually reserved for more complicated functions. See Function Basics for details.
You don’t have to define it as a function if you don’t want to — it will simply execute as a statement instead, although you could not then use it as a function later in your code — however in your original Question you specified that it is a function. See What Is a Function Handle? for an extended discussion.

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Plus de réponses (1)

Ali Zain
Ali Zain le 6 Jan 2020

0 votes

y= function(t)=[0.2582;
-0.3631 cos(0.21910*(t);
0.3572 cos(0.4158)(t);
0.3473*cos(0.6180t);
0.3336*cos(0.8135t);
0.3162*cos(t);
0.2954*cos(1.1756t);
0.2714*cos(1.3383t);
0.2443*cos(1.4863t);
0.2146*cos(1.6180t);
0.1826*cos(1.7321t);
0.1485*cos(1.8271t);
0.1128*cos(1.902t);
-0.0759*cos(1.9563t);
0.0382*cos(1.9890t)]
why it is giving error...

1 commentaire

Star Strider
Star Strider le 6 Jan 2020
Except for the second line, there is no multiplication operator.

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