Putting Consecutive numbers into variables

I data in this format a=[1;2;3;7;0;6;7;8;9;2;4;3;14;15;16;17;0;9;2];

what I need to accomplish is to put consecutive numbers into different variables...

in this case the expected outcome is a1=[1;2;3]; a2=[6;7;8;9]; a3=[14;15;16;17]; How do I

[Stephen23]

"what I need to accomplish is to put consecutive numbers into different variables... "

Do NOT do this. Dynamically accessing variable names is one way that beginners force thmeselves into writing slow, complex, obfuscated, buggy code that is hard to debug:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Your code will be simpler and much more efficient if you simply use one container variable (e.g. a cell array, as my answer shows).

Answer 1

[Stephen23]

>> A = [1;2;3;7;0;6;7;8;9;2;4;3;14;15;16;17;0;9;2];
>> D = diff([false;diff(A(:))==1;false]);
>> F = @(b,e)A(b:e);
>> C = arrayfun(F,find(D>0),find(D<0),'UniformOutput',false);
>> C{:}
ans =
    1
    2
    3
ans =
    6
    7
    8
    9
ans =
   14
   15
   16
   17

You can access the data in the cell array C using basic indexing:

https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

[DARLINGTON ETAJE]

Thank You...you are amazing

[DARLINGTON ETAJE]

F = @(b,e)A(b:e);

Hello Stephen Cobeldick

Please explain what b and e mean

are they variables...I don't know how to use them for a new dataset

[Walter Roberson]

b and are are dummy parameter names, similar to

function result = F(b, e)
   result = A(b, e)
end