Not able to append to an empty container map

3 vues (au cours des 30 derniers jours)
Sanjan Das
Sanjan Das le 15 Juil 2019
Commenté : Sanjan Das le 15 Juil 2019
I've been trying to write a function that divides a matrix based on its 'class value' . For example, if we have an matrix like -
1 2 1
3 4 0
1 3 1
6 7 2
6 7 0
6 7 1
we should get
(class 1)
1 2 1
1 3 1
6 7 1
and
(class 0)
3 4 0
6 7 0
and
(class 2)
6 7 2
I've written this so far using a container map, since I want to closely represent a Python dictionary.
I want to create a new key-value pair in the map if the class in focus is not already a key of the map. And if it already exists as a key, I want to append it to the existing value (which is a matrix) for that key.
function [separated] = separateByClass(dataset)
% assume the class variable is the last column of the dataset
% We return a container map mapping the unique class variables to the
% row instances from the dataset
separated = containers.Map;
for i=1:size(dataset, 1)
vector = dataset(i, :);
class_var = vector(end);
if isKey(separated, class_var)== 0
separated(class_var) = vector;
else
separated(class_var) = [separated(class_var); vector];
end
end
end
Using the same matrix used as an example as the input 'dataset', I get an error on the first iteration of the for loop, on trying to run the line
separated(class_var) = vector;
The error I get is
Error using containers.Map/subsasgn
Specified key type does not match the type expected for this container.
Error in separateByClass (line 12)
separated(class_var) = vector;
I can't figure how to fix the data type issue in this!

Réponse acceptée

Walter Roberson
Walter Roberson le 15 Juil 2019
https://www.mathworks.com/help/matlab/ref/containers.map.html
The default key type is char, so use the keytype valuetype options to change the default.
  1 commentaire
Sanjan Das
Sanjan Das le 15 Juil 2019
Yes, changed the type to 'any', and works now! Thanks.

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