Subscript in stackedplot DisplayLabels

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Sebastian Sprunck
Sebastian Sprunck le 18 Juil 2019
Modifié(e) : Yair Altman le 13 Fév 2024
Hello everyone,
I'm trying to build a stacked plot with 3 graphs using Matlab 2018b's stackedplot-function. I'd like to write the corresponding DisplayLabels in TeX-style so that I can use subscripts, as can be done in regular plots without problem using e.g.
'T_{r}'
When I create a stackedplot using below code though, the labels are printed 'as is' instead of as a subscript:
s = stackedplot(f,If,'DisplayLabels',{'T_{r} = 50 ns','T_{r} = 20 ns','T_{r} = 10 ns'});
StackedPlot.PNG
I've tried accessing Interpreter-properties and even setting
set(0,'defaultTextInterpreter','latex');
but couldn't get it to work as intended.
Can anyone please tell me how to do that?
Best regards
Sebastian
  4 commentaires
Sebastian Sprunck
Sebastian Sprunck le 30 Juil 2019
Hmmm, I suspected something like that. Guess that's the curse of new functionalities ;)
Building my own subplot was my first attempt, but I'd like the x axis to only show at the bottom, as is the case in the stackedPlot variant. If I could get the labels to work as I want them, it would mean much "cleaner" code for my script.
Adam Danz
Adam Danz le 30 Juil 2019
Modifié(e) : Adam Danz le 30 Juil 2019
Yeah, there are a few newer plotting functions that have a bunch of features on lockdown such as heatmap() and stackedplot(). I avoid using them which is unfortunate since they have some nice added features but when you can edit the basic, they become less useful.

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Yair Altman
Yair Altman le 31 Juil 2019
Modifié(e) : Yair Altman le 13 Fév 2024
You can access the individual stacked-axes' properties via the hidden sub-property Axes of the stackedplot's AxesProperties property, and then modify the YLabel's Interpreter property to 'tex' or 'latex' (it's 'none' by default).
For example, to change the middle (2nd) YLabel:
s = stackedplot(...);
drawnow % ensure that the plot is updated before proceeding
axesProps = struct(s.AxesProperties(2)); % using struct() is undocumented
axesProps.Axes.YLabel.Interpreter = 'tex';
Note that using struct() to access internal object properties is undocumented.
  6 commentaires
Ron
Ron le 4 Fév 2024
Modifié(e) : Ron le 4 Fév 2024
Thankyou for responsding sir but I did try but it didnt do anything except the warning.
or there is something wrong with my code??
ss=stackedplot(error,'LineWidth',1.5);
ss.DisplayLabels = [sample_name,sample_name(1)+"_{abc}"];
axesProps = struct(ss.AxesProperties(4)); % using struct() is undocumented
axesProps.Axes.YLabel.Interpreter = 'tex';
Adam Danz
Adam Danz le 13 Fév 2024
The call to struct in this context is undocumented. It needs to be called after the stackplot is generated. This can be done by adding a drawnow before calling struct.

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