Transforming HH:mm:SS to 'dd.MM.yy HH:mm:SS' and loosing seconds

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Butterflyfish
Butterflyfish le 22 Juil 2019
Commenté : Butterflyfish le 22 Juil 2019
>> time = datestr(seconds(duration),'HH:MM:SS')
time =
'02:59:57'
>> date_and_time = datetime(time, 'ConvertFrom', 'datenum', 'Format', 'dd.MM.yy HH:mm:SS')
date_and_time =
datetime
22.07.19 02:59:00
I would like to add current date to the 'time'. Why do I loose the 57 seconds when I do this transformation, and how to do it correctly?
Many thanks!
  2 commentaires
Stephen23
Stephen23 le 22 Juil 2019
Modifié(e) : Stephen23 le 22 Juil 2019
I am surprised that this does anything at all, and does not simply throw an error:
>> time = datestr(seconds(duration),'HH:MM:SS') % a date string...
>> date_and_time = datetime(time, 'ConvertFrom', 'datenum',...)
% ^^^^^^^ but here datenum!
Given that the variable time is a character vector (with a date representation), why are you telling datetime that the input is a serial date number?
More importantly, why are you converting a much better duration object to a datestring anyway? If you want a datetime object at the output then I don't see why you need any intermediate (almost) obsolete date strings or date numbers.
Butterflyfish
Butterflyfish le 22 Juil 2019
What I actually would like to do eventually is add a duration to a date and time, to get a date and time output.
E.g.
22.07.19 14:30 + 5400 seconds = 22.07.19 16:00
I thus wanted to formation the duration to the the date to make an addition. I would love to know how to do it in an easier way!

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Stephen23
Stephen23 le 22 Juil 2019
Modifié(e) : Stephen23 le 22 Juil 2019
"I would like to add current date to the 'time'"
Sure, that is easy, by just adding a duration object to a datetime object.
You do not write what class the very badly-named duration is, but the simplest solution is to add a duration array to the datetime object of the current time:
>> D = seconds(1375.143) % a duration object
D =
1375.1 secs
>> T = datetime() % a datetime object (current time)
T =
22-Jul-2019 13:19:37
>> X = D+T % add them together!
X =
22-Jul-2019 13:42:32
  3 commentaires
Steven Lord
Steven Lord le 22 Juil 2019
Stephen Cobeldick has given you a better approach. But to explain why your original approach appeared to lose the seconds, look at the table of values that you can use to create the Format for a datetime in the datetime documentation. In the Format, using the characters s or ss displays the number of whole seconds and using the characters S, SS, ... SSSSSSSSS displays the number of fractional seconds. The case of the S matters.
So you didn't actually lose the seconds, you just were displaying the 0 fractional seconds instead of the 57 whole seconds.
Butterflyfish
Butterflyfish le 22 Juil 2019
Ah, that makes even more sense, thanks for this explanation!

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