how to fill gaps in a matrix with a numbers using interpolation to develop a contour.
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
M.S. Khan
le 27 Juil 2019
Commenté : M.S. Khan
le 30 Juil 2019
M =
0 0 0
0 0 3
0 3 0
3 0 3
0 3 0
0 0 3
3 0 0
0 0 0
in this M matrix, using interpolation i want to fill gaps with 3s between any 3s. for example, in first column, first 3 is in the 4th row and last 3 is in the 7th row. i want to fill rows 5 and 6 also with 3s. same for other columns.
Thanks and regards for all cooperation
1 commentaire
Réponse acceptée
Andrei Bobrov
le 27 Juil 2019
Modifié(e) : Andrei Bobrov
le 27 Juil 2019
M(cumsum(M) & cumsum(M,1,'reverse')) = 3;
or for:
M =[0 0 0; 2 2 3; 3 3 0; 0 0 0; 3 3 0; 2 2 3; 0 0 0; 3 3 2; 0 0 0; 3 3 3];
s = join(string(M)','');
[a,b] = regexp(s,'30+3');
lo = false(size(M));
for ii = 1:numel(a)
for jj = 1:numel(a{ii})
lo(a{ii}(jj)+1:b{ii}(jj)-1,ii) = true;
end
end
M(lo) = 3;
Plus de réponses (1)
KALYAN ACHARJYA
le 27 Juil 2019
Modifié(e) : KALYAN ACHARJYA
le 27 Juil 2019
M =[0 0 0
0 0 3
0 3 0
3 0 3
0 3 0
0 0 3
3 0 0
0 0 0]
[rows colm]=size(M);
for i=1:colm
idx=find(M(:,i)==3);
idx_update=idx(1):1:idx(end);
M(idx_update,i)=3;
end
M
Loop can be avoided. Wait for experts comments.
Result:
M =
0 0 0
0 0 3
0 3 3
3 3 3
3 3 3
3 0 3
3 0 0
0 0 0
5 commentaires
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!