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Division by an OptimizationVariable not supported.

Asked by BOWEN LI on 27 Jul 2019
Latest activity Edited by Matt J
on 30 Jul 2019
Hi everyone,
I met a problem that in my equation, there is a part where includes a division of two optimization varaibles. For example, if i let
y=optimvar('y',[4,1,4],'Type','integer','LowerBound',0,'UpperBound',1);
then my equation would be like: (1-yi)/sum(yi)
However, matlab says division of two optimization variable is not supported by optimization toolbox, while I don't think i can change the form of my equation. So I
'm wondering if it's possible to proceed.
Thank you!

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1 Answer

Answer by Matt J
on 27 Jul 2019
Edited by Matt J
on 27 Jul 2019
 Accepted Answer

The problem-based solver is largely limited to linear and (in R2019) quadratic programs. If you find yourself computing non-linear/non-quadratic OptimizationExpressions, it will typically mean that you have a more general optimization problem than that and must resort to another solver.
Or, you could try to reformulate your problem as a linear problem, but to know if that is possible, we would have to see the full problem, not just a single expression that occurs in it somewhere.

  5 Comments

Probably ga(). It is the only solver which can handle non-linear problems with integer constraints.
hi,I just got an idea that if it's possible to use fcn2optimexpr to convert my non-linear equations to be used by optimization toolbox?
for example, if i want to convert hb(t)
hb(t)=2*sqrt(2*(1-yi(1,:,t))*d/vb+sum((1-yi(1,:,t))*td)*ub./(sum((1-yi(:,:,t)).*qij(:,:,t))));
I may want to use fcn2optimexpr in this way:
hb(t)=fcn2optimexpr(@(2*sqrt(2*(1-yi(1,:,t))*d/vb+sum((1-yi(1,:,t))*td)*ub/(sum((1-yi(:,:,t)).*qij(:,:,t))))),yi);
but there's something wrong with the syntax tho.
Thank you!
Here is a list of Supported Operations on Optimization Expressions and Variables. You will have to go through your operations and see which are not on the list. It appears, for example, that sqrt is not there.

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