Sum the values of an matrix

Hi ,

given a matrix

SU = [1 0 1 0 1 0 1 1 1 0 1 0 0;
      0 0 0 1 1 0 0 1 0 1 0 0 0;
      1 1 1 0 0 0 0 0 1 1 1 0 0]
  

I want to assign the value 6 to all the 1 of the first raw, 3 to all the 1 of the second raw, 2 to all the 1 of the third raw. Obtaining:

      SU = [6 0 6 0 6 0 6 6 6 0 6 0 0;
            0 0 0 3 3 0 0 3 0 3 0 0 0;
            2 2 2 0 0 0 0 0 2 2 2 0 0]
        

Then I want to create a vector B that contain the sum of all the column. for example, the first element of B should be equal to 6+0+2=8. Obtaining

      B = [8 2 8 3 9 0 6 9 8 5 8 0 0] 
      

Does someone help me to write this code?

Thanks

[Adam Danz]

1) SU is a matrix, not a vector.

2) I think you meant to assign a value of 2 to the third column, not 3, based on the B summation.

Answer 1

[Adam Danz]

% SU Matrix
SU = [1 0 1 0 1 0 1 1 1 0 1 0 0;
    0 0 0 1 1 0 0 1 0 1 0 0 0;
    1 1 1 0 0 0 0 0 1 1 1 0 0];

% Replace 1 with 6,3,2 in 1st, 2nd, 3rd rows respectively 
% This assumes all values in SU are either 1 or 0.
SU = SU .* [6;3;2];

% If the above assumption is incorrect use this line instead.
% SU = (SU==1) .* [6;3;2]

% Sum columns
B = sum(SU,1)