Hi Everone,
I have a question in relation to the .
I fed into the MAtlab 2019a a simple instruction, i.e., mean of two variables (example underneath) and it would not solve it anyway
imean1=mean(abs(i_min_1(1,1)),i_max_1(1,1));
If I use it in a translated mathematical formula like underneath:
imean1=(abs(i_min_1(1,1))+i_max_1(1,1))/2;
then it works flwalwssly and very fine proceed with calculation.
Please let me know what could go wrong with it.
Many thanks in advance.
Andras

 Réponse acceptée

Adam
Adam le 8 Août 2019

0 votes

doc mean
shows you the syntax of the mean function. It expects an array, not multiple arguments. Generally you take the mean of more than 2 inputs so having them as individual arguments would not be sensible.
mean( [ abs(i_min_1(1,1)),i_max_1(1,1) ] );
should work.

1 commentaire

Stephen23
Stephen23 le 8 Août 2019
Andras Gergely's incorrectly accepted "Answer" moved here:
Thanks Adam.
I followed a different synthax to solve my issue but this is one also works.
By now it is clear.
Many thanks for that.

Connectez-vous pour commenter.

Plus de réponses (1)

Andras Gergely
Andras Gergely le 8 Août 2019

0 votes

Thanks MAdhan RAvi!
Best wishes. :)

Catégories

Produits

Version

R2019a

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by