How to work the Mean function
6 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi Everone,
I have a question in relation to the .
I fed into the MAtlab 2019a a simple instruction, i.e., mean of two variables (example underneath) and it would not solve it anyway
imean1=mean(abs(i_min_1(1,1)),i_max_1(1,1));
If I use it in a translated mathematical formula like underneath:
imean1=(abs(i_min_1(1,1))+i_max_1(1,1))/2;
then it works flwalwssly and very fine proceed with calculation.
Please let me know what could go wrong with it.
Many thanks in advance.
Andras
0 commentaires
Réponse acceptée
Adam
le 8 Août 2019
doc mean
shows you the syntax of the mean function. It expects an array, not multiple arguments. Generally you take the mean of more than 2 inputs so having them as individual arguments would not be sensible.
mean( [ abs(i_min_1(1,1)),i_max_1(1,1) ] );
should work.
1 commentaire
Stephen23
le 8 Août 2019
Andras Gergely's incorrectly accepted "Answer" moved here:
Thanks Adam.
I followed a different synthax to solve my issue but this is one also works.
By now it is clear.
Many thanks for that.
Plus de réponses (1)
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!