Finding location of minimum in 3d array

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DARLINGTON ETAJE
DARLINGTON ETAJE le 14 Août 2019
Commenté : DARLINGTON ETAJE le 14 Août 2019
Consider this code
Y = rand(1000,100) ;
iwant = zeros(20,50,100) ;
uwant=zeros(50,1,100);
for i = 1:100
Y1 = Y(:,i) ;
S1 = numel(Y1); % this is same always 1000
iwant(:,:,i) = reshape(Y1(1:S1 - mod(S1, 20)), 20, []);
uwant(:,:,i) = sum(iwant(:,:,i), 1).' / 20;
A=uwant(:,:,1:100);
B=abs(A-z);
C=min(B,[],[2 3]);
end
C is 50 by 1. Each value in C is selected from each row of 100 variables. How can I know the location where C is taking from among the 100 variables

Réponse acceptée

KSSV
KSSV le 14 Août 2019
It is asked multiple times..you may search in the forum. For EXample:
  2 commentaires
DARLINGTON ETAJE
DARLINGTON ETAJE le 14 Août 2019
Thanks for your response...the code there doesnt work...please help me with codes specific to this question.
DARLINGTON ETAJE
DARLINGTON ETAJE le 14 Août 2019
please help me out

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