Finding location of minimum in 3d array
7 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
DARLINGTON ETAJE
le 14 Août 2019
Commenté : DARLINGTON ETAJE
le 14 Août 2019
Consider this code
Y = rand(1000,100) ;
iwant = zeros(20,50,100) ;
uwant=zeros(50,1,100);
for i = 1:100
Y1 = Y(:,i) ;
S1 = numel(Y1); % this is same always 1000
iwant(:,:,i) = reshape(Y1(1:S1 - mod(S1, 20)), 20, []);
uwant(:,:,i) = sum(iwant(:,:,i), 1).' / 20;
A=uwant(:,:,1:100);
B=abs(A-z);
C=min(B,[],[2 3]);
end
C is 50 by 1. Each value in C is selected from each row of 100 variables. How can I know the location where C is taking from among the 100 variables
0 commentaires
Réponse acceptée
KSSV
le 14 Août 2019
It is asked multiple times..you may search in the forum. For EXample:
2 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Linear Algebra dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!