Average H of hsv
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I want to divide a picture of 640*480 pixels to 16*16 blocks and get average value H of every block. The result shoud be a 40*30 array. But I tried mean function, the result always is a 1*16 array.
1 commentaire
Jan
le 11 Sep 2012
Please post the code. It is impossible to debug "I tried mean function".
Réponses (3)
Rene
le 11 Sep 2012
A = rand(480,640);
B=[];
for i=1:16:480
for j=1:16:640
B = [B,mean(mean(A(i:i+15,j:j+15)))];
end
end
B = reshape(B,30,40);
should do the trick
note: inefficient for large matrices
Sean de Wolski
le 11 Sep 2012
Modifié(e) : Sean de Wolski
le 11 Sep 2012
Why not use blockproc() like I suggested in the other thread? It will do this for you completely automagically - there is no reason to reinvent the wheel.
bm = blockproc(H,[16 16],@(blk)mean(blk.data(:)));
4 commentaires
Jan
le 11 Sep 2012
The Reshape/Sum method is faster than Blockproc. I think, this is a reason.
Sean de Wolski
le 11 Sep 2012
Of course it's faster - but it still is only taking 7/100ths of a second for the 480x640 image above...
Sean de Wolski
le 11 Sep 2012
0.06 seconds with a little more intelligence in anonymous function creation:
blksz = [16 16];
n = 16^2;
bm = blockproc(H,blksz,@(blk)sum(sum(blk.data))./n);
Jan
le 11 Sep 2012
Ok, Sean. I admit one 640x480 picture is tiny. Then I claim that the Resahpe/Sum approach is simpler that Blockproc with an anonymous function. But this is not a convincing argument also: Both solutions can be used by copy&paste now, such that the "programming" will need a few seconds only.
I avoid to suggest the faster C-Mex function http://www.mathworks.com/matlabcentral/fileexchange/24812-blockmean, which I have published after the "mean over blocks"-questions have been written repeatedly. Here the speed advantage will be eaten up by the time reuquired to install the C-compiler...
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