How to iterate with fsolve to find Mach number

1 vue (au cours des 30 derniers jours)
Hailey
Hailey le 10 Sep 2019
Modifié(e) : Torsten le 10 Sep 2019
I'm trying to interate static pressure ratio to find Mach number using fsolve, but I can't get the syntax correct. The Mathworks explaination didn't really help me. Could anyone out there help?
I have a set range for the pressure ratio, but the Mach number is unknown. Here is the equation:
Capture.PNG
This is what I have so far for the code:
pt2pinf = [1.9, 2.7, 3.5, 4.3, 5.1, 5.9, 6.7, 7.5, 27.5, 47.5, 67.5 ,87.5 ,107.5,127.5, 147.5, 200, 252.5, 305, 357.5, 410, 462.5 ,515 ,567.5, 620, 672.5, 725, 777.5, 830 ,882.5, 935, 987.5, 1000];
Me0=ones(1,32);
g=1.2;
pt2pinf_test = fsolve(@(Me)(((1+((g-1)/2)*Me.^2)^(g/(g-1)))/((((2*g)/(g+1))*Me.^2)-((g-1)/(g+1)))),Me0);
  8 commentaires
Torsten
Torsten le 10 Sep 2019
They are stored in the fsolve return parameter (pt2pinf_test in your case).
Hailey
Hailey le 10 Sep 2019
Modifié(e) : Hailey le 10 Sep 2019
The values are too small to be a Mach number after a shock wave.
Not sure what I did wrong.

Connectez-vous pour commenter.

Réponse acceptée

Torsten
Torsten le 10 Sep 2019
Modifié(e) : Torsten le 10 Sep 2019
function main
pt2pinf = [1.9, 2.7, 3.5, 4.3, 5.1, 5.9, 6.7, 7.5, 27.5, 47.5, 67.5 ,87.5 ,107.5,127.5, 147.5, 200, 252.5, 305, 357.5, 410, 462.5 ,515 ,567.5, 620, 672.5, 725, 777.5, 830 ,882.5, 935, 987.5, 1000];
Me0 = 5.0;
g = 1.2;
fun = @(Me,pquot)((((1+((g-1)/2)*Me.^2).^(g/(g-1)))./((((2*g)/(g+1))*Me.^2)-((g-1)/(g+1))))-pquot).^2
for i = 1:numel(pt2pinf)
pquot = pt2pinf(i);
machnumber(i) = fminsearch(@(Me)fun(Me,pquot),Me0,optimset('TolFun',1e-10));
end
machnumber
fun(machnumber,pt2pinf)
end

Plus de réponses (0)

Catégories

En savoir plus sur Partial Differential Equation Toolbox dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by