Find specific date/time from a series of datenums
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I have a 7184x72001 double matrix where the first column is a list of serial datenumbers.
I am happy to keep the format this way, but I need to be able to select a specific date/time from this list so that I can extract the data from certain days/times that I am interested in.
So, is it either possible to:
-search from a list of datenums to find a specific date/time that I provide?
-add a column of str data to a matrix of double?
or-convert all of the datenums to date and time?
I have tried the second approach so far:
D=csvread('Tiritiri5280_PSD_1sHammingWindow_50%Overlap_output.csv'); %load in data
t=D(:,1); %extract time column
formatOut='yymmddHHMMSS';
times=datestr(t, formatOut); %convert t column datenums to date and time
rows=(1:length(times)).'; %number of dates and times we have
D_new=[rows D]; %add new column to D
D_new(:,1)=timeslist(:,2); %add times in different format to D
-this works but I now get the datenum in a different format which is also not readable. How do I keep the date time in yymmddhhmmss in a double matrix? Is this possible?
Here,column 1 is the new dates/times that I tried to insert in readable form, and column 2 is serial datenum.

2 commentaires
Nicolas B.
le 17 Sep 2019
Hi,
in a matrix, you have the problem that you can only have 1 data type for all your data. Maybe a cell array could help you?
Louise Wilson
le 17 Sep 2019
Réponse acceptée
Plus de réponses (1)
Ted Shultz
le 17 Sep 2019
It looks like the start of your approach is reasonable. Once you make a “times” array, there is no need to add it back to the “D” matrix. You can use that as your index.
For example:
indexOfInterest = (times > t_one) && (times < t_two);
someData =d(indexOfInterest, :);
1 commentaire
Louise Wilson
le 17 Sep 2019
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