How do I remove leading characters from a string?
6 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
pruth
le 18 Sep 2019
Commenté : Walter Roberson
le 19 Sep 2019
I read one ascii file. and created this dummy mat file (attached ).
To make simple matrix out of it i need to split the string
i used this code (below) but it coudnt split the first string which is a date and time with some leading number since there is no space in between. There is this number before the date and time, i want remove those numbers so can use datenum on that string !
for i = 1:len_data
segments = regexp(dummy{1,1}{i,1},' ', 'split');
end
0 commentaires
Réponse acceptée
Walter Roberson
le 18 Sep 2019
segments = regexp(dummy{1,1}{i,1}, '\t', 'split');
Perhaps you could have used readtable() on the ascii file: it would likely have detected the tab delimiter.
3 commentaires
Walter Roberson
le 18 Sep 2019
strjoin(segments(2:3), ' ')
Note that we no longer recommend using datenum: we recommend using datetime()
Plus de réponses (1)
Ankit
le 18 Sep 2019
Hello Pruth,
a = extractBetween(dummy{1, 1}, 10,20)
where 10 is the start position and 20 is the end position.
Cheers
Ankit
3 commentaires
Ankit
le 18 Sep 2019
hello pruth,
cell data can be converted to double using str2double. But you can't use it to convert date, it will return a NaN value.
thanks
Ankit
Walter Roberson
le 19 Sep 2019
However, datetime() is happy to process cell array of character vectors ;-)
Also, in newer releases, duration() is happy to process cell array of character vectors. This was not possible in older releases.
Voir également
Catégories
En savoir plus sur Characters and Strings dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!