Could anyone help me how to group into 4 sets.

I ma having a matrix
A=[2 3 1 4 5 6]
i used the command
NN = num2cell(num2cell(A),2)
,which gives the following result
{2} {3} {1} {4} {5} {6}
If i use the command
NN= num2cell(num2cell(A,2),2)
it gives the following result
{1 2 3 4 5 6}
Could anyone help me how to get the result in the following manner
{2 3} {1 4 5} {6}

1 commentaire

What if criterion of grouping?
Why
{2 3} {1 4 5} {6}
And not
{2 3} {1 4 5 6}

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Réponses (1)

Raj
Raj le 20 Sep 2019
Use this:
NN = mat2cell(A,[1],[2,3,1])

4 commentaires

jaah navi
jaah navi le 22 Sep 2019
When A=[2 3 1 4 5 6] the above command executes and gives me the result.
I tried the following command with A=[1 2 3 4;
2 3 1 4;
1 4 2 3]
but it gives error stating Input arguments, D1 through D2, must sum to each dimension of the input
matrix size, [3 4].'
Could you please help me on it.
madhan ravi
madhan ravi le 22 Sep 2019
Modifié(e) : madhan ravi le 22 Sep 2019
Raj seemed to have answered our original question. What is your desired result? Didn’t you figure it out of how to use mat2cell() still (after 10 questions)?
Stephen23
Stephen23 le 22 Sep 2019
Modifié(e) : Stephen23 le 22 Sep 2019
jaah navi: you have been using MATLAB for more than two years.
During that time you have asked us every ten minutes to solve basic problems for you, most of which you could solve yourself by reading the documentation.
Rarely do you make any attempt to understand what an error message is telling you.
Rather than relying on us to write your very basic code for you, perhaps you should start reading documentation, trying examples, looking at FEX submissions, debugging, and doing it yourself. Note that this is in your interest because you would actually make progress much faster than you are now.
Your current approach to writing code (relying on other people to write every step of your algorithm and relying on other people debugging every tiny error message) is, in the long term, not efficient.
darova
darova le 22 Sep 2019
+1

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le 20 Sep 2019

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