I need to multiply the Diff () = dVdt [1369 x 1] with V [1370 x 1] equation. How can I add to the lenght of dVdt? I need to add three terms together and their Matrix Dimeions must match. See error below:
Matrix dimensions must agree.
Error in homework_1_P2 (line 40)
Inertia = (1.1*Mv*(dVdt).*V)./1000; % kW
load CYC_FUDS.mat
t = cyc_mph(:,1); % Time [s]
Vmph = cyc_mph(:,2); % Velocity [mph]
V = Vmph.*(1609/3600); % Velocity [m/s]
dVdt = (diff(V)./diff(t)); % Accel. m/s^2
% Aerodynamic = (0.5*pa*Cd*Af*V.^3)./1000; % kW
% Rolling = ((Cr*Mv*g*cos(Xa)).*V)./1000; % kW
Inertia = (1.1*Mv*(dVdt).*V)./1000; % kW
% Pw = (Aerodynamic+Rolling+Inertia); % kW

 Réponse acceptée

James Tursa
James Tursa le 21 Sep 2019
Modifié(e) : James Tursa le 21 Sep 2019

0 votes

You could use V(2:end) or V(1:end-1) instead of V in that line. Or maybe average the two.

5 commentaires

Jose Cruz
Jose Cruz le 21 Sep 2019
Thank you, this works! I realized with your anwer that I should use V(1:end-1) throught all my equations.
Walter Roberson
Walter Roberson le 21 Sep 2019
gradient()
Jose Cruz
Jose Cruz le 21 Sep 2019
Is gradient meant to be used with funtions or will it work with numerical (emperical) values loaded from .mat?
Walter Roberson
Walter Roberson le 21 Sep 2019
There are two versions of gradient(). One of them works with symbolic functions or symbolic expressions; the other works with numeric matrices.
Jose Cruz
Jose Cruz le 21 Sep 2019
Thank you! I'll have to try with the gradient and see how it compares to using V(1:end-1).

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