How to use interp1 to stretch out smaller vector to the size of larger vector?

33 vues (au cours des 30 derniers jours)
So I have two vectors, lets call them A and B. A is the smaller vector, and has 1260 columns. B is the larger vector and has 1778 columns. I want to take an average of both these vectors. This is being hard because they are different sizes. Is there a way for me to use interp1 so that I can stretch out the smaller vector to match the size of the larger vector? Any help would be really appreciated!

Réponse acceptée

John D'Errico
John D'Errico le 30 Sep 2019
Modifié(e) : John D'Errico le 30 Sep 2019
Assuming that you intend to create a vector of averages, do this:
Ahat = interp1(1:1260,A,linspace(1,1260,1778));
C = (Ahat + B)/2;
  2 commentaires
Zuha Yousuf
Zuha Yousuf le 2 Oct 2019
Thank you so much! You have no idea how much this has helped me!
SURESH KUMAR
SURESH KUMAR le 19 Jan 2024
it helped me alot . I wanted to strech the time series data without changing the y axis values and it does perfectly however i had to come up with understading about the duration for which i wanted my expension.. Anyways Thanks
Here is my if anyone needs
powNew=interp1(1:legnth(A),A,linspace(1,legnth(A),legnth(A)+increasementYourValue))

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Statistics and Machine Learning Toolbox dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by