How to use interp1 to stretch out smaller vector to the size of larger vector?
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Zuha Yousuf
le 30 Sep 2019
Commenté : SURESH KUMAR
le 19 Jan 2024
So I have two vectors, lets call them A and B. A is the smaller vector, and has 1260 columns. B is the larger vector and has 1778 columns. I want to take an average of both these vectors. This is being hard because they are different sizes. Is there a way for me to use interp1 so that I can stretch out the smaller vector to match the size of the larger vector? Any help would be really appreciated!
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John D'Errico
le 30 Sep 2019
Modifié(e) : John D'Errico
le 30 Sep 2019
Assuming that you intend to create a vector of averages, do this:
Ahat = interp1(1:1260,A,linspace(1,1260,1778));
C = (Ahat + B)/2;
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SURESH KUMAR
le 19 Jan 2024
it helped me alot . I wanted to strech the time series data without changing the y axis values and it does perfectly however i had to come up with understading about the duration for which i wanted my expension.. Anyways Thanks
Here is my if anyone needs
powNew=interp1(1:legnth(A),A,linspace(1,legnth(A),legnth(A)+increasementYourValue))
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