how to modify a structure?
Afficher commentaires plus anciens
Hello. I initialize (instantiate) a structure like this:
YourStruct = struct(...
'Date', {cell(2208,1)}, ...
'Hour', {zeros(2208,1)}, ...
'DryBulb', {zeros(2208,1)}, ...
'DewPnt', {zeros(2208,1)}, ...
'SYSLoad', {zeros(2208,1)}, ...
'NumDate', {zeros(2208,1)});
'Date' has 92 days, and 'Hour' has 24 hours, from 1 to 24. How can I express 'Date' and 'Hour' in serial date numbers and how do I present these serial date numbers in 'NumDate'? Thank you.
7 commentaires
Image Analyst
le 16 Sep 2012
Please format properly (as Code).
UPT
le 16 Sep 2012
UPT
le 16 Sep 2012
Walter Roberson
le 16 Sep 2012
Please go back and edit your original posting to mark-up the code there.
Note: there is no "i" in my username.
UPT
le 16 Sep 2012
Modifié(e) : Oleg Komarov
le 16 Sep 2012
Walter Roberson
le 16 Sep 2012
Blank line before and after the code. Indent the code.
Réponses (1)
Walter Roberson
le 16 Sep 2012
NumDate = Data.Date + (Data.Hour - 1) / 24;
5 commentaires
Walter Roberson
le 16 Sep 2012
Wait -- what exactly does the Date cell contain?
UPT
le 16 Sep 2012
Walter Roberson
le 16 Sep 2012
As strings? If so then use datenum() to convert them to serial date numbers and add (Hour-1)/24
UPT
le 17 Sep 2012
Walter Roberson
le 17 Sep 2012
Your Hour field is the same length as your Date field, which suggests you want exactly 1 hour conversion for each Date converted, rather than wanting to create 24 hour conversions for each Date converted.
data.NumDate = datenum(Data.Date) + (Data.Hour - 1) / 24;
except that you might need to add an additional parameter to datenum() in order to indicate the date format.
Catégories
En savoir plus sur Time Series Objects dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!