relative error: Error using ==> mtimes

6 vues (au cours des 30 derniers jours)
NH
NH le 16 Sep 2012
Hello I am trying to get the relative error for sinx=sqrt(1-cos^2(x) and getting error with this matlab code:
clear
clc
x=logspace(-1,-10,10);
lhs=sin(x);
t=cos(x);
rhs=sqrt(1-cos(x)*cos(x));
abserr=abs(lhs-rhs);
Rel=abs((lhs-rhs)/lhs);
disp('x error rel.error')
disp('--------------------')
for i=1:10
disp(sprintf('%22.15e %22.15e %22.15e\n',x(i),abserr(i),Rel(i)))
end
end
??? Error using ==> mtimes Inner matrix dimensions must agree.
Error in ==> Q at 6 rhs=sqrt(1-cos(x)*cos(x));
any idea? thanks

Réponse acceptée

Jan
Jan le 16 Sep 2012
Modifié(e) : Jan le 16 Sep 2012
rhs = sqrt(1 - cos(x) .* cos(x))
While * performs the matrix multiplication, .* multiplies elementwise.

Plus de réponses (1)

NH
NH le 16 Sep 2012
thank you thats solved the problem. Now after i run it i get this new error:
?? Attempted to access Rel(2); index out of bounds because numel(Rel)=1.
Error in ==> Q at 11 disp(sprintf('%22.15e %22.15e %22.15e/n',x(i),abserr(i),Rel(i)))
clear
clc
x=logspace(-1,-10,10);
lhs=sin(x);
rhs=sqrt(1-cos(x).*cos(x));
abserr=abs(lhs-rhs);
Rel=abs((lhs-rhs)/lhs);
disp('x error rel.error')
disp('--------------------')
for i=1:10
disp(sprintf('%22.15e %22.15e %22.15e\n',x(i),abserr(i),Rel(i)))
end
end
  2 commentaires
Jan
Jan le 17 Sep 2012
Modifié(e) : Jan le 17 Sep 2012
  1. Please post a new thread for a new problem.
  2. Use the debugger to find the reasons for the size of Rel: Set a breakpoint in the line Rel=abs((lhs-rhs)/lhs) to find out, that exactly the same argument of matrix versus elementwise operations concerns the division also. Therefore you need ./ instead of / . Surprised?
NH
NH le 17 Sep 2012
1. Thank you, next time I will. 2. Wow! thank you fore your advice exactly what I needed.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Operators and Elementary Operations dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by