How do I use a for loop on ever element in an array?

7 vues (au cours des 30 derniers jours)
Bryce Johnson
Bryce Johnson le 3 Oct 2019
Commenté : Bryce Johnson le 3 Oct 2019
I need to use the if and elseif statements to modify the original values in the d array and spit out the new array according to the statements inside. Long story short how do I get an array back from a for loop? a needs to be the modified array.
d =([8 4 0.5 -3]);
for a = 1:length(d)
if d<0
d(a) = 2*cosd(d);
elseif d <= 0 & d <= 1
d(a) = 5*(d)^(1/3);
elseif d < 1 & d < 7
d(a) = ceiling(1/factorial(d));
elseif d >= 7
d(a) = 20*log(d)*(log10(d));
end
end

Réponse acceptée

Jess Lovering
Jess Lovering le 3 Oct 2019
I think that the below code is what you are asking about. Your if requirements seem like they may be off, however, so I changed those as well. And there is no function called "ceiling" but I put in ceil which is a rounding up command that you may be looking for.
d =([8 4 0.5 -3]);
for ii = 1:length(d)
if d(ii)<0
a(ii) = 2*cosd(d(ii));
elseif d(ii) >= 0 & d(ii) <= 1
a(ii) = 5*(d(ii))^(1/3);
elseif d(ii) > 1 & d(ii) < 7
a(ii) = ceil(1/factorial(d(ii)));
elseif d(ii) >= 7
a(ii) = 20*log(d(ii))*(log10(d(ii)));
end
end
  1 commentaire
Bryce Johnson
Bryce Johnson le 3 Oct 2019
Ah yes thank you very much that did solve it, it came up with the wrong answers but that was not your fault, I wrote the problem down wrong. You did help me get the function working though I appreatie that!

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