Sorry, no message is displayed. But the result in not a 3d matrix where the values are computed at each node above the surface. I obtain a 1x1x11 matrix.
where is the error?
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Hi, running the following script:
% Create a data set:
x = rand(100,1)*4 - 2;
y = rand(100,1)*4 - 2;
S = x.*exp(-x.^2-y.^2) * 1000;
% Construct the interpolant:
F = TriScatteredInterp(x,y,S);
% Evaluate the interpolant at the locations [XI,YI].
XI = -2:0.25:2;
YI = -2:0.1:2;
[XImat,YImat] = meshgrid(XI,YI);
ZImat = F(XImat,YImat);
% Define a set of ZI locations
ZI = -500:100:500;
% Find the node above the surface S
BW = false(length(YI),length(XI),length(ZI));
for i = 1:length(YI)
for j = 1:length(XI)
BW(i,j,:) = ZImat(i,j)<ZI;
end
end
KImat = zeros(size(ZImat));
for i = 1:length(YI)
for j = 1:length(XI)
firstIndex = find(BW(i,j,:),1);
if ~isempty(firstIndex)
KImat(i,j) = firstIndex;
end
end
end
% Create a 3d grid where to compute a value at each node above the surface S
[X,Y,Z] = meshgrid(XI,YI,ZI);
for i = 1:length(YI)
for j = 1:length(XI)
if KImat(i,j) == 1
for i = 1:length(Y)
for j = 1:length(X)
for k = 1:length(Z)
T_geotherm(i,j,k) = 18 + 0.003 .* (Z(i,j,k));
end
end
end
end
end
end
dislay this message: 'Attempted to access Z(1,1,12); index out of bounds because size(Z)=[41,17,11].'
where is the error?
Thanks, Gianluca
4 commentaires
Wayne King
le 17 Sep 2012
The variable, T_geotherm, is not being generated because your if statement if KImat(i,j) == 1 is never true
Réponse acceptée
Jan
le 17 Sep 2012
Modifié(e) : Jan
le 17 Sep 2012
Matlab code gets much cleaner and easier to debug, when vectorization is applied:
Ugly and due to a missing pre-allocation slow in addition:
for i = 1:length(Y)
for j = 1:length(X)
for k = 1:length(Z)
T_geotherm(i,j,k) = 18 + 0.003 .* (Z(i,j,k));
end
end
end
Beautiful and fast:
T_geotherm = 18 + 0.003 .* Z;
Btw, using nested loops with the same counter is not really clean, but not an error:
for i = 1:length(YI)
for j = 1:length(XI)
if KImat(i,j) == 1
for i = 1:length(Y)
for j = 1:length(X)
It is strongly recommended to avoid such confusing constructions.
Plus de réponses (1)
Wayne King
le 17 Sep 2012
I can run this without error. I think you have some variable in your workspace that is conflicting with this and causing the error.
Can I suggest you first clear the workspace and then try to run this script?
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