How to Regrid the netcdf data in order to achieve smaller/greater spatial resolution?

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BN
BN le 6 Oct 2019
Commenté : Suman le 14 Nov 2023
I have a netcdf file with 0.5*0.5 degree (Lat*Lon) grided resolution for precipitation from 1982-2015 in all around the globe. now I want to interpolate (regrid) this file to 0.25*0.25 degree without changing the time. In fact I want to interpolate the precipitation data in 0.25*0.25 lat and lon.
please help me with this issue. If it is possible a sample code can really helpful for me.
Best Regards,
Behzad

Réponses (2)

Chad Greene
Chad Greene le 7 Oct 2019
Hey Behzad,
This is pretty straightforward: Just use interp2.
When reading the data from the NetCDF file you might need to rotate and flip the grid to get the orientation right, but then let longitude act as the x variable and let latitude act as the y variable.
You can create the quarter-degree grid in one step with cdtgrid like this:
[lati,loni] = cdtgrid(1/4);
or you can create it manually by
[loni,lati] = meshgrid(min(lon):1/4max(lon),max(lat):-1/4:min(lat));
Then use interp2 like
zi = interp2(lon,lat,z,loni,lati);
Hope that helps.
  3 commentaires
O.Hubert
O.Hubert le 16 Mar 2022
You probably figured it out by now, but the error you have arises because you try to transpose a 3-dimensional array (longitude, latitude, time) using a shorthand for 2-dimensional arrays. If you want to transpose longitude and latitude without touching the time dimension, use:
new_array = permute(old_array,[2 1 3]);

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abbas zoulikha
abbas zoulikha le 11 Nov 2020
i have the same error in my script how did you resolved this errors ?

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