Convert transfer function to state-space models
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I'm trying to convert a transfer function to state space model. In order to avoid the control toolbox functions since I don't have it's license.
The transfer function that I'm using is quite simple. Is the model for a heatsink temperature.
For this transfer function I have the next values for A,B,C and D.
I've tried to compare the output from the lsim() function and the equations from above but the output differs

Here's the code that I've used
P = rand(1,10)*1000;
t = 0:1:length(P)-1;
A = -400;
B = 0.5;
C = 0.6658;
D = 0;
%%%%%%%%%%%%%%%%%%%%%%%%%
%%% State space %%%
%%%%%%%%%%%%%%%%%%%%%%%%%
state_space_sys = ss(A,B,C,D);
state_space = lsim(state_space_sys,P,t);
figure
plot(t,state_space)
grid on,grid minor, title('State space')
%%%%%%%%%%%%%%%%%%%%%%%%%
%%% My function %%%
%%%%%%%%%%%%%%%%%%%%%%%%%
x(1:length(P)) = 0;
y(1:length(P)) = 0;
u = P;
for k = 1:length(u)
x(k+1) = A*x(k) + B*u(k);
y(k) = C*x(k) + D*u(k);
end
figure
plot(t,y)
grid on,grid minor, title('My function')
Is there any mistakes on the approach?
It should be quite simple, but I can't manage to find the solution.
7 commentaires
Star Strider
le 11 Oct 2019
Note that:
becomes:
in the state space realisation.
Diego Garcia
le 11 Oct 2019
Modifié(e) : Diego Garcia
le 11 Oct 2019
Star Strider
le 11 Oct 2019
No.
The state space equaiton you wrote would be integrated into:

if I integrated it correctly, or here:

that you can easily simplify.
Diego Garcia
le 11 Oct 2019
What is Rth? What does th stand for in Rth?
Maybe you should use:
state_space_sys = ss(A,B,C,D,[]);
command to have your system as a discrete model and then compare, i got similar plots in that case.
Walter Roberson
le 16 Oct 2019
Modifié(e) : Walter Roberson
le 16 Oct 2019
Is there a reason not to use tf() and ss() ? That is, if you pass a tf into ss() then it will be converted.
Diego Garcia
le 17 Oct 2019
Réponse acceptée
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