can any one correct me this code please??
Afficher commentaires plus anciens
Can you correct me this code to draw the 4 axis (major axe, minor axe and the 2 diagonal and ortogonal axes) not the ellipse
bw = imread('13.jpg');
bw = bwlabel(bw);
imshow(bw)
s = regionprops(bw, 'Orientation', 'MajorAxisLength', ...
'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
xbar = s.Centroid(1);
ybar = s.Centroid(2);
a = s.MajorAxisLength/2;
b = s.MinorAxisLength/2;
theta = pi*s.Orientation/180;
R = [ cos(theta) sin(theta)
-sin(theta) cos(theta)];
xy = [a*cosphi; b*sinphi];
xy = R*xy;
x = xy(1,:) + xbar;
y = xy(2,:) + ybar;
plot(x,y,'r','LineWidth',2);
hold off
thanks
4 commentaires
Azzi Abdelmalek
le 18 Sep 2012
what is J on line2 ?
Pamela Paolo
le 18 Sep 2012
Azzi Abdelmalek
le 18 Sep 2012
what is k? have you read errors messages?
Pamela Paolo
le 18 Sep 2012
Réponses (4)
bwlabel works on a 2D matrix, Your 13.jpg image is probably a color (rgb) image and hence is a 3 dimensional matrix. You could convert it to grayscale ( which is a 2d matrix)
bw2 = imread('13.jpg');
% bw2= rgb2gray(bw2); If image is binary
bw2 = bwlabel(bw2);
imshow(bw2)
s = regionprops(bw2, 'Orientation', 'MajorAxisLength', ...
'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
xbar = s.Centroid(1);
ybar = s.Centroid(2);
a = s.MajorAxisLength/2;
b = s.MinorAxisLength/2;
theta = pi*s.Orientation/180;
R = [ cos(theta) sin(theta)
-sin(theta) cos(theta)];
xy = [a*cosphi; b*sinphi];
xy = R*xy;
x = xy(1,:) + xbar;
y = xy(2,:) + ybar;
plot(x,y,'r','LineWidth',2);
hold off
% ADDED EDIT
plot(s.Centroid(1),s.Centroid(2),'*')
line(s.Centroid(1)-a:s.Centroid(1)+a,s.Centroid(2));
line(s.Centroid(1),s.Centroid(2)-b:s.Centroid(2)+b);
4 commentaires
Pamela Paolo
le 18 Sep 2012
Pamela Paolo
le 18 Sep 2012
Image Analyst
le 19 Sep 2012
I think it's because you asked for major and minor axis when what you want does not match regionprops definition of those. See my answer.
Azzi Abdelmalek
le 18 Sep 2012
Modifié(e) : Azzi Abdelmalek
le 18 Sep 2012
The corrected code
bw = imread('13.jpg');
bw = bwlabel(bw);
imshow(bw)
s = regionprops(bw, 'Orientation', 'MajorAxisLength', ...
'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
xbar = s.Centroid(1);
ybar = s.Centroid(2);
a = s.MajorAxisLength/2;
b = s.MinorAxisLength/2;
theta = pi*s.Orientation/180;
R = [ cos(theta) sin(theta) ;-sin(theta) cos(theta)];
xy = [a*cosphi; b*sinphi];
xy = R*xy;
x = xy(1,:) + xbar;
y = xy(2,:) + ybar;
plot(x,y,'r','LineWidth',2);
hold off
1 commentaire
Pamela Paolo
le 18 Sep 2012
Pamela Paolo
le 18 Sep 2012
0 votes
2 commentaires
Thomas
le 19 Sep 2012
I have edited my code .. Please try it and see if it works..
Image Analyst
le 19 Sep 2012
Pamela, people are giving you what you asked for which I don't think is what you want. See my answer.
Image Analyst
le 19 Sep 2012
Modifié(e) : Image Analyst
le 19 Sep 2012
0 votes
Pamela, My guess is that you really mean Feret Diameter ( http://www.sympatec.com/Science/Characterisation/05_ParticleShape.html) rather than the major and minor axis of an ellipse fitted to the shape. Am I correct? Feret diameter will touch at least two points on the perimeter of the object, like a caliper distance, while an ellipse's axes won't necessarily have the axis endpoints on the shape's perimeter.
MATLAB does not provide Feret diameters. You can calculate it yourself using bwboundaries. Let me know if you can't figure it out. I don't have any code all ready to give you though. However, you might take a look at this File Exchange submission: http://www.mathworks.com/matlabcentral/fileexchange/30402-feret-diameter-and-oriented-box
6 commentaires
Pamela Paolo
le 19 Sep 2012
Image Analyst
le 19 Sep 2012
Then why isn't the elliptical fit working for you? Can you upload your image somewhere so we can see your objects?
Pamela Paolo
le 19 Sep 2012
Modifié(e) : Pamela Paolo
le 3 Jan 2013
Image Analyst
le 19 Sep 2012
I didn't run any of their code. Does they not draw lines along the major and minor directions? If they don't, I could help. If they do, then what's the problem? Do you not know how to chop your region up into quadrants? If you do, then what do you do with the pixels? Why don't you look at image moments: http://en.wikipedia.org/wiki/Image_moments, http://homepages.inf.ed.ac.uk/rbf/CVonline/LOCAL_COPIES/OWENS/LECT2/node3.html to determine symmetry?
Pamela Paolo
le 19 Sep 2012
Modifié(e) : Pamela Paolo
le 19 Sep 2012
Image Analyst
le 19 Sep 2012
PCA would probably be good. I don't have any PCA code to share with you, sorry.
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