Alternation without for loop

I have 2 vectors that I want to alternate

A = [1 2 3 4 5 6 7 8 9 10]
B = [0.5 0.2 0.4 0.8 0.9]

I would like to have the following output (preferably without for loop)

Output = [1 0.5 2 0.2 3 0.4 4 0.8 5 0.9 6 7 8 9 10]

How to do this?

Thanks!

Answer 1

[Stephen23]

>> N = min(numel(A),numel(B));
>> V = [reshape([A(1:N);B(1:N)],1,[]),A(N+1:end),B(N+1:end)]
V =
  1  0.5  2  0.2  3  0.4  4  0.8  5  0.9  6  7  8  9  10

[J. Alex Lee]

nice...i like when i didn't see the obvious complete opposite path...and i learned a new thing with the empty argument for reshape

Answer 2

[Jos (10584)]

% a sorting trick
A = [1 2 3 4 5 6 7 8 9 10]
B = [0.5 0.2 0.4 0.8 0.9]
C = [A B] ;
[~,ix] = sort([1:numel(A) 1:numel(B)])
C = C(ix)

Answer 3

[J. Alex Lee]

Here's a possibility: if A and B were guaranteed to be the same length (your example is not) and row vectors, you could do

N = length(A)
Output = reshape([A(:),B(:)]',2*N,1)

If not same length, you can nan-pad the shorter vector and remove later.