How to create a new table array combining the values every n,th element from two different table arrays

I have two table arrays with a big number of rows and one column each. Each array has a different size. I would like to add the values from the second array into the first so that every n values of A the same number of values of B are added to create a new table array C.

For example:

Given a matrix A=[2,5,7,9,11,13,15,17,19,21] and a matrix B= [1,1,1,1,1,1,3,3,3,3,3,3,4,4,4,4,4,6,6,6,6,6,6]

I would like to create a new matrix C = [2,5,1,1,1,1,1,7,9,3,3,3,3,3,3,11,13,4,4,4,4,4,15,17,6,6,6,6,6,6,19,21]

In this case every 2 values of A, 5 consecutive values from B are added.

In my case I would like to add every 60 values of A to add 59 consecutive values of B. The length of A is 2008x60= 120480 rows and B is 2008x59= 118472 rows.

[Guillaume]

Your example has alternatively 5 or 6 values from B added. That doesn't match your description.

Note that tables and arrays are two different things.

[Danae Parissi]

I am sorry for the typo, the number of values that are added from B are contantly 49.

Also they are all table arrays.

Answer 1

[Guillaume]

In my case I would like to add every 60 values of A to add 59 consecutive values of B

So, assuming that A and B are indeed vectors

C = reshape([reshape(A, 59, []); reshape(B, 60, [])], 1, [])

Basically, reshape A in columns of 59 rows, reshape B in columns of 60 rows, concatenate the two matrices vertically and reshape back into a vector.

[Danae Parissi]

Thank you very much it works. Would you also know how to add 3 table arrays in a similar fashion?

I am simply doing what you showed me in sequence but I was wondering if there were something more elegant.

[Guillaume]

Again, a table array is not a thing. A table is a completely different thing from an array.

If the 3 arrays to interlace are separate variables, it's the same principle:

reshape([reshape(A, Astride, []);  ... where Astride is 59 in your example
         reshape(B, Bstride, []);  ... where Bstride is 60 in your example
         reshape(C, Cstride, [])], ...
        1, [])

If the arrays are stored in a cell array instead, there are simpler ways.