Can someone help me how to add 2 hexadecimal numbers? I would appreciate the help and sentiment.
I tried using: c=dec2hex(hex2dec(a)+hex2dec(b)));
But it didn't work. Is there a correct way to do this?

 Réponse acceptée

Robert U
Robert U le 17 Oct 2019

1 vote

Hi Jed Louise Lesma,
Despite the extra bracket in your code (I removed it), the method you tried should work:
a = '3afb';
b = '2839';
c=dec2hex(hex2dec(a)+hex2dec(b));
Kind regards,
Robert

3 commentaires

Jed Louise Ledesma
Jed Louise Ledesma le 17 Oct 2019
Hello Robert,
Thank you for replying! Sorry about the extra bracket my eyes were kinda hazy.
Can this code also be used in a gui?
c=dec2hex(hex2dec(a)+hex2dec(b));
I tried inputting it like this:
a = str2double(get(handles.edit1, 'String'));
b = str2double(get(handles.edit2, 'String'));
c = dec2hex(hex2dec(a)+hex2dec(b));
but it responded with this:
Error using hex2dec>hex2decImpl (line 58)
Input to hex2dec should have just 0-9, a-f, or A-F.
Robert U
Robert U le 17 Oct 2019
The "hex"-values are supposed to be given as char. Thus the str2double()-command should be deleted.
Kind regards,
Robert
Jed Louise Ledesma
Jed Louise Ledesma le 17 Oct 2019
I appreciate what you did.
Thank you!

Connectez-vous pour commenter.

Plus de réponses (2)

Steven Lord
Steven Lord le 17 Oct 2019

2 votes

If you're using release R2019b or later, you can enter hexadecimal numbers directly.
>> 0x3afb + 0x2839
ans =
uint16
25396
>> hex2dec('3afb')+hex2dec('2839')
ans =
25396
Walter Roberson
Walter Roberson le 17 Oct 2019

1 vote

If there is a possibility that the user might enter hex values with more than 53 significant bits then you should use sscanf with %lx format instead of hex2dec.

Catégories

En savoir plus sur Environment and Settings dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by