Effacer les filtres
Effacer les filtres

Getting rid of a for loop

6 vues (au cours des 30 derniers jours)
jacob Mitch
jacob Mitch le 19 Oct 2019
Commenté : jacob Mitch le 20 Oct 2019
If I have my code as
function [value1, value2] = scope(input)
c=1;
x=length(input);
for z=2:x
if z==x
break
elseif input(z-1)>input(z) && input(z)<input(z+1)
value1(c,1)=z;
value2(c,1)=input(z);
c=c+1;
end
end
Is it possible to get rid of the for look so the function runs without loops. Thank you.

Réponse acceptée

Walter Roberson
Walter Roberson le 19 Oct 2019
value1 = find(input(1:end-2) > input(2:end-1) & input(2:end-1) < input(3:end)) + 1;
value2 = input(value1);
  1 commentaire
jacob Mitch
jacob Mitch le 20 Oct 2019
Perfect Walter, Thank you

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Plus de réponses (2)

Turlough Hughes
Turlough Hughes le 19 Oct 2019
Modifié(e) : Turlough Hughes le 19 Oct 2019
The following should do the job.
ind=input(1:end-2)>input(2:end-1) & input(2:end-1)<input(3:end);
ind=[false; ind; false]; % If input is a row vector just remove to semi-colons here.
value1=find(ind);
value2=input(ind);

Steven Lord
Steven Lord le 20 Oct 2019
You're looking for a local minimum in your vector input? [I would choose a different name, BTW, since input already has a meaning.] If so and you're using release R2017b or later use islocalmin.

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