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Question about making a function file with vectors and variables

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Portgas Ace
Portgas Ace le 20 Sep 2012
Clôturé : MATLAB Answer Bot le 20 Août 2021
Question deleted by James. Partially restored by Matt Fig:
a part of my program has syntax that looks like this,
for n=1:1:A1 if (Z(n)<3 | Z(n)>9 | Z(n)~=Z(n)) disp('One or more of the element/s is/are not included.'); return;
elseif ~isnumeric(Z(n)) disp('There is error') return; end
so if i enter:
function_name ([3 4 A], [4 5 6])
matlab says: Undefined function or variable 'A'.
  2 commentaires
Jan
Jan le 20 Sep 2012
Why do you delete your question? Then the work of the once, who wanted to help you, is lost. Not friendly.
Matt Fig
Matt Fig le 21 Sep 2012
OP:
a part of my program has syntax that looks like this,
for n=1:1:A1 if (Z(n)<3 | Z(n)>9 | Z(n)~=Z(n)) disp('One or more of the element/s is/are not included.'); return;
elseif ~isnumeric(Z(n)) disp('There is error') return; end
so if i enter:
function_name ([3 4 A], [4 5 6])
matlab says: Undefined function or variable 'A'.

Réponses (4)

Wayne King
Wayne King le 20 Sep 2012
Modifié(e) : Wayne King le 20 Sep 2012
MATLAB will do that on its own.
>> clear A % in case A is in the workspace
>> a=[1 2 A 4]
The MATLAB error message will be:
Undefined function or variable 'A'.
  1 commentaire
Portgas Ace
Portgas Ace le 20 Sep 2012
but im using a function file. im only required to input a vector with only numbers as value and if i entered a non-number, i should show an error. so ex, a = [1 2 A 4]; there should be an error saying ive entered a wrong input. something like that. :(

Wayne King
Wayne King le 20 Sep 2012
If A is not a variable in the workspace, then inputting it into a function will cause an error
function sumout = testfunction(input1 )
sumout = sum(input1);
end
If you call that function with
>>sumout = testfunction([1 2 3 A 4]);
throws an error. You can always use isnumeric() if you want
if ~isnumeric(input)
error( )
end
  1 commentaire
Portgas Ace
Portgas Ace le 20 Sep 2012
Modifié(e) : Portgas Ace le 20 Sep 2012
hope this solves my problem. thank you! :D

Jan
Jan le 20 Sep 2012
After A = 1; a = [1,2,A,4]; there is no method to detect, if a has been created using numbers, functions or other variables. When A is e.g. a character array, it is converted to double implicitly:
A = 'Z';
a = [1, 2, A, 4] % ==> [1, 2, 90, 4]
Here A is converted to the type DOUBLE and the ASCII value 90 is stored. Afterwards a is a double vector as all its elements have the same type.
I think, you have a different problem. Perhaps you want to test the class of A before inserting into the vector.

Portgas Ace
Portgas Ace le 20 Sep 2012
a part of my program has syntax that looks like this,
for n=1:1:A1 if (Z(n)<3 | Z(n)>9 | Z(n)~=Z(n)) disp('One or more of the element/s is/are not included.'); return;
elseif ~isnumeric(Z(n)) disp('There is error') return; end
so if i enter:
function_name ([3 4 A], [4 5 6])
matlab says: Undefined function or variable 'A'.

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