How do you determine the average values in second column of an excel data corresponding to a particular range of values in first column ?
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I have an excel file which containes more than 300000 in both column a and b. If the values in first column is less than 1 ,I need to average the corrosponding values in the second column and then increasing the range to 1 to 2 and so on up to 30..Any help would be greatly appreciated. Thank you.
My file looks like this
2.2060 0.3120
2.2140 0.3138
2.2180 0.3146
2.2260 0.3164
3.8920 0.2611
3.9000 0.259
3.9070 0.2571
3.8840 0.2632
3.9600 0.2431
4.0010 0.2322
If the values in first column is less than 1 ,I need to average the corrosponding values in the second column and then increasing the range to 1 to 2 and so on up to 30..Any help would be greatly appreciated. Thank you.
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Nicolas B.
le 21 Oct 2019
For that situation, the easiest way is to select data based on a criteria. For example, if your table is named t:
indRows = t(:,1) < 1; % get row indexes for values below 1
myMean = mean(t(indRows, 2)); % compute the mean
Of course, you can also merge the 2 line of codes to avoid using indRows.
2 commentaires
Duphrin
le 21 Oct 2019
Nicolas B.
le 21 Oct 2019
Then, I think that would be the easiest solution to simply loop with your criterias. I could imagine solutions based on the function discretize(), but it wouldn't avoid a loop:
mylim = [-inf, 1:30, inf]; % list of your limits
y = discretize(t, mylim); % you get the indexes
m = NaN(size(myLim)); % your output vector
for n = 1:numel(m) % loop to get the mean value
m(n) = mean(t(y == n), 'omitnan');
end
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