Time table code using while loops

Answer 1

[Mandy Downs]

function outputMatrix = timesTable( sizeOfTable)

    % Insert code to determine the size of the times table
    sizeOfTable = abs(sizeOfTable);
    sizeOfTable = floor (sizeOfTable);
    rows = sizeOfTable;
    columns = sizeOfTable;
    % Insert code to initialize the table by filling all entries with zeros
    outputMatrix (1:rows, 1:columns) = [0];
    % Insert code to fill the first column and first row with consecutive integers 
    % starting with 1
    i = 1;
    while (i <= sizeOfTable)
        outputMatrix (i, 1) = i;
        outputMatrix (1, i) = i;
        i = i + 1;
    end
    % Use a loop structure to fill the remaining entries in the times table
    i = 1;
    while (i <= sizeOfTable)
        j = 1;
        while (j <= sizeOfTable)
            outputMatrix (i, j) = i * j;
            j = j + 1;
        end
        i = i + 1;
    end
end

[Kemuel Roberts]

this is good but it leaves all other elements in the array (except for 1st row and 1st column) with a value of zero.

[Brandon Heil]

You can also do this I understand the assignment is asking for a while loop but thats very complicated compared to this.

function outputMatrix = timesTable(sizeOfTable)

sizeOfTable = abs(sizeOfTable);

A =[1:1:sizeOfTable];

B=A';

outPutMatrix = B*A

Answer 2

[David Hill]

Not sure why you have to use a while loop.

function T = timesTable(n)
T=1:n;
count=2;
while count<=n
    T(count,:)=count*T(1,:);
    count=count+1;
end