simple for loop problem

Create a for loop that adds one to every number in the array. For example [1,2,3] becomes [2,3,4] after the loop is complete.

a. create the variable x=1:10;

b. set the loop to run the correct amount of times

c. write the loop

d. use disp(x)

[per isakson]

Sounds like homework. What you done so far and what's your problem?

[Jia-Cheng]

x = [1:10]

x = 1×10

1 2 3 4 5 6 7 8 9 10

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x_1 =0

x_1 = 0

for i = 1:length(x)
    x_1= x_1 + x(i)+1
end

x_1 = 2

x_1 = 5

x_1 = 9

x_1 = 14

x_1 = 20

x_1 = 27

x_1 = 35

x_1 = 44

x_1 = 54

x_1 = 65

disp(x)

     1     2     3     4     5     6     7     8     9    10

Answer 1

[Maz M. Khansari]

The following will do the job for you.

x = 1:10;
x_new = zeros(1,numel(x));

for i=1:numel(x)
    x_new(i) = x(i)+1;
end

disp(x);

     1     2     3     4     5     6     7     8     9    10

Answer 2

[Darshan]

x = [1:10]

x = 1×10

1 2 3 4 5 6 7 8 9 10

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for i=1:10
    new_x(i,:) = x(i)+1
end

new_x = 2

new_x = 2×1

2 3

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new_x = 3×1

2 3 4

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new_x = 4×1

2 3 4 5

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new_x = 5×1

2 3 4 5 6

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new_x = 6×1

2 3 4 5 6 7

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new_x = 7×1

2 3 4 5 6 7 8

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new_x = 8×1

2 3 4 5 6 7 8 9

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new_x = 9×1

2 3 4 5 6 7 8 9 10

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new_x = 10×1

2 3 4 5 6 7 8 9 10 11

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