Array indices must be positive integers or logical values.

1 vue (au cours des 30 derniers jours)
Dominic Nightingale
Dominic Nightingale le 23 Oct 2019
clc;
clear all;
x=1;
h=10;
f = @(x) sin(((x^2+x)))
for n = 1:10
df(n-1) = (f(x+(h^(n-1)) - f(x)))/(h^n-1)
end
not sure what I am doing wrong to get this error.

Réponses (1)

Johannes Fischer
Johannes Fischer le 23 Oct 2019
The first entry in any kind of Matlab vector/array/matrix... is indexed with 1 (and not 0, as for example in C++). That is why you get an error in the first iteration of your for loop.
Two options:
adjust the indieces for df
for n = 1:10
df(n) = (f(x+(h^(n-1)) - f(x)))/(h^n-1);
end
or, in Matlab you can get rid or the for loop and matalb calculates the resulting array in a single line, in many cases this is faster than usinng for loops
n = 1:10;
df = (f(x+(h^(n-1)) - f(x)))/(h^n-1);

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by