Adding two arrays of different sizes together evenly without messing cumulative sum.

7 vues (au cours des 30 derniers jours)
I have 2 arrays.
A = [0 1 2 3 4 5 6 . . . . n] % Size 2402 x 1, assume in this case n number is 58
B = [18] % Size 1x1
C = [Cumulative output of A+B] % expected result starting from 0 and ending at 76 @ size of 2402 *1
Now
A is a cummulative sum of energy consumed starting from 0 and ending at 58 kWh during 2402 seconds.
B is total auxiliary energy consumed during 2402 seconds. Please note B is not a cumulative energy. Its just a number in 1 x 1 array.
What I am trying to do is to add B to A evenly such that the result C can be a cumulative result starting from 0 and ending at 76.
I tried a lot of logics but nothing worked for me.
Kindly guide me in correct direction to acheive this result.

Réponse acceptée

Akira Agata
Akira Agata le 24 Oct 2019
Based on the question, C should be a cumulative result starting from 0. So, it should be:
C = A + linspace(0,B,length(A));
  2 commentaires
Shahab Khan
Shahab Khan le 24 Oct 2019
Hi, Thanks its works. However, the C array is in the form of 2402 x 2402. I actually need it in the form of 2402 x 1 or 1 x 2402.
Shahab Khan
Shahab Khan le 24 Oct 2019
Modifié(e) : Shahab Khan le 24 Oct 2019
Ok I managed to do it myself in this maner.
First I tried to understand linespace function. When I understood how it works. I write this code to acheive the above goal.
A = [0 1 2 3 4 . . . . n]; % Size 2402 x 1
B = [18];
D = linspace(0,B,length(A));
E = D';
C = A + E; % Size 2402 x 1
Thanks for the help.

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 24 Oct 2019
Modifié(e) : Walter Roberson le 24 Oct 2019
C = cumsum(A + B / length(A));

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