using fscanf to open file
Afficher commentaires plus anciens
clear all
TOL=[10^-3 10^-4 10^-5 10^-6 10^-7 10^-8 10^-9]
fileID = fopen('relp1.dat'); formatSpec = '%f';
A1= fscanf(fileID,formatSpec)
fclose(fileID);
fileID = fopen('relp2.dat');
[A2]= fscanf(fileID,'%f')
fileID = fopen('relp3.dat');
[A3]= fscanf(fileID,'%f')
% sorting the data
A1INT=[A1(1,:) A1(3,:) A1(5,:) A1(7,:) A1(9,:) A1(11,:) A1(13,:)]
A1ND=[ A1(2,:) A1(4,:) A1(6,:) A1(8,:) A1(10,:) A1(12,:) A1(14,:)]
A2INT=[A2(1,:) A2(3,:) A2(5,:) A2(7,:) A2(9,:) A2(11,:) A2(13,:)]
A2ND=[ A2(2,:) A2(4,:) A2(6,:) A2(8,:) A2(10,:) A2(12,:) A2(14,:)]
A3INT=[A3(1,:) A3(3,:) A3(5,:) A3(7,:) A3(9,:) A3(11,:) A3(13,:)]
A3ND=[ A3(2,:) A3(4,:) A3(6,:) A3(8,:) A3(10,:) A3(12,:) A3(14,:)]
i keep runnnig into this error
Error using fscanf
Invalid file identifier. Use fopen to generate a valid file identifier.
Error in relp_dat (line 4)
A1= fscanf(fileID,formatSpec)
Réponses (1)
Walter Roberson
le 27 Oct 2019
filename = 'relp1.dat';
[fileID, msg] = fopen(filename);
if fileID < 0
error('could not open file "%s" because: "%s"', filename, msg);
end
I suspect that you will find that the filename is wrong with confusion between lower case L and digit 1, or else that the file is in a different directory.
Catégories
En savoir plus sur Standard File Formats dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!