Creating random vector with 10 different lengths

I can't seem to ceate a random vector from 1-10k then 1-20k then 1-30k consectuively until 100k logging different values.

Here is the code I have so far:

inc=[10000 20000 30000 40000 50000 60000 70000 80000 90000 100000];
for l=1:length(inc) %creating a loop to go through the 10 values of inc
    vec1 = randi(1,inc(l));  %geenrating random vector from 1-respective value of inc

Any help would be appreciated

Answer 1

[Image Analyst]

You need to tell it either one row or one column. Try this:

inc = [10000, 20000 30000, 40000, 50000, 60000, 70000, 80000, 90000, 100000];
maxValue = 100000; % Whatever you want the potential max value in the vector to be.
for k = 1 : length(inc) % Creating a loop to go through the 10 values of inc
	% Generating random vector from 1-respective value of inc.
	vec1 = randi(maxValue, 1, inc(k)); % or randi(maxValue, inc(k), 1);
	fprintf('Made a vector with %d rows and %d columns.\n', size(vec1, 1), size(vec1, 2));
end

[Chelles Rees]

Thank you!

Answer 2

[per isakson]

Documentation on randi says:

X = randi(imax,n) returns an n-by-n matrix of pseudorandom integers drawn from the discrete uniform distribution on the interval [1,imax].

Thus, randi(1,inc(l)); will return a matrix of ones the same as ones(inc(l)).

vec1 is overwritten in each iteration of the loop. Is its value stored in another variable?