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How to I plot 3D level surfaces of this 4D function?

6 vues (au cours des 30 derniers jours)
Jessica Peterson
Jessica Peterson le 13 Nov 2019
Commenté : Walter Roberson le 13 Nov 2019
I have the following function. I wish to plot the 3D surface of the function when density equals 100000, 80000, 60000, 40000. I am unsure how to plot a function of 3 variables. Thanks
density= @(x,y,z)10.^5 -24000.*z + 10.^4.*sech((0.75.*x-1.5).^2+(y-1).^2)

Réponses (1)

Walter Roberson
Walter Roberson le 13 Nov 2019
Use ndgrid or meshgrid to create a 3D grid of x, y, z locations, and evaluate the function at those points . Suppose we call the result D .
Now use
arrayfun(@(LEVEL) isosurface(x, y, z, D, LEVEL), [100000, 80000, 60000, 40000]);
It is not possible to pass multiple levels to isosurface() in one call.
  4 commentaires
Jessica Peterson
Jessica Peterson le 13 Nov 2019
That creates a 2D plot of a rectangle. I am trying to make a 3D plot.
Walter Roberson
Walter Roberson le 13 Nov 2019
Grab the plot with your cursor and rotate it. Or give the command
view(3)

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