Effacer les filtres
Effacer les filtres

Quick vectorization question (for loop)

2 vues (au cours des 30 derniers jours)
Tanmay
Tanmay le 27 Sep 2012
Hi
This loop takes about 0.085 seconds to execute and needs to be executed several thousand times. Is there a way you think I can vectorize this? I really appreciate any help!
wsize = 20;
vin = rand(1200,1);
for idx = wsize:length(vin)
mstd(idx-wsize+1, :) = std(vin(idx-wsize+1:idx));
end
PS: I don't have Parallel Processing toolbox.

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Matt Fig
Matt Fig le 27 Sep 2012
Modifié(e) : Matt Fig le 27 Sep 2012
I hope you are pre-allocating your mstd vector. Other than that, this is about 6 times faster. I didn't compare to stdfilt.
for idx = wsize:length(vin)
x = vin(idx-wsize+1:idx);
x = x-sum(x)./ wsize;
mstd(idx-wsize+1, :) = sqrt(sum(x.^2)/(wsize-1));
end
.
.
.
EDIT add comparison based on IA's recommendation
I find the above to not be faster than using stdfilt when repeatedly run. Here is what I used for comparison:
mstd2 = stdfilt(vin,[0;ones(wsize,1)]);
mstd2 = mstd2(wsize/2:end-wsize/2);
There might be a better way to do this with stdfilt, I have no real experience with the function and had to figure it out based on trial and error and doc reading... Perhaps IA can comment.
  1 commentaire
Tanmay
Tanmay le 27 Sep 2012
yes, I had pre-allocated this vector. Nice trick there! Thanks!

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Plus de réponses (1)

Image Analyst
Image Analyst le 27 Sep 2012
Do you have the Image Processing Toolbox? it looks like your code is a sliding window of a standard deviation filter. This is done by the function stdfilt() in the Image Processing Toolbox. Alternatively (if you don't have the Image Processing Toolbox) you could use an anonymous function and blockproc (I have a demo for that if you need it).
  1 commentaire
Matt Fig
Matt Fig le 27 Sep 2012
I had never heard of stdfilt, IA. Thanks!

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