Why is dsolve returning an arbitrary constant?

9 vues (au cours des 30 derniers jours)
David Winthrop
David Winthrop le 25 Nov 2019
I have the following differential equation I want to solve from a simple harmonic motion problem.
diffeq.png
When I enter this into MATLAB including two initial conditions, I get an arbitrary constant even though there should not be one. Why?
>> syms y(t) g L c
S = dsolve(diff(diff(y(t))) -L*y - g == 0, y(0) == c,diff(y(0))== 0)
S =
exp(-L^(1/2)*t)*(c - C5 + g/L) - g/L + C5*exp(L^(1/2)*t)

Réponse acceptée

David Goodmanson
David Goodmanson le 25 Nov 2019
Modifié(e) : David Goodmanson le 25 Nov 2019
Hi David,
you need slightly different syntax.
syms y(t) g L c
Dy = diff(y)
S = dsolve(diff(diff(y(t))) -L*y - g == 0, y(0) == c,Dy(0)== 0)
S =
(exp(L^(1/2)*t)*(g + L*c))/(2*L) - g/L + (exp(-L^(1/2)*t)*(g + L*c))/(2*L)
Also, assuming k/m = w0^2 is positive as usual, then for harmonic motion the sign of the k/m term needs to change.
syms y(t) g c w0
Dy = diff(y)
S = dsolve(diff(diff(y(t))) +w0^2*y - g == 0, y(0) == c,Dy(0)== 0)
S =
g/w0^2 - (exp(-t*w0*1i)*(- c*w0^2 + g))/(2*w0^2) - (exp(t*w0*1i)*(- c*w0^2 + g))/(2*w0^2)

Plus de réponses (0)

Catégories

En savoir plus sur Symbolic Math Toolbox dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by