Hello,
U is cell:
U =
1×2 cell array
[1×2 double] [1×2 double]
>> U{1}
ans =
1 2
>> U{2}
ans =
2 3
T= []
T has the union of element of U 1 2 3
S = {}; is empty in the first time
I want to test each value of T if exist in U and the coy U{ i } in S, my S will be:
S={ { 1 2 }, {{1 2} {2 3}}, {2 3} }

1 commentaire

dpb
dpb le 26 Nov 2019
Show precisely how you think you built the output S array...

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 Réponse acceptée

Philippe Lebel
Philippe Lebel le 26 Nov 2019
Modifié(e) : Philippe Lebel le 26 Nov 2019

0 votes

here is my try:
U{1} = [1,2];
U{2} = [2,3];
T = [1,2,3];
S = {};
for i = 1:length(T)
temp_cell = {};
k=1;
for j = 1:length(U)
if ismember(T(i),U{j})
temp_cell{k} = U{j};
k=k+1;
end
end
S{i} = temp_cell;
end
The only difference with what you explained in your question is that the elements in U are lists, not cells. (ismember() does not work on cells)

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