Delete end points from columns in a structure array

Hello.

I have a structure array S (1 x 50000) with 10 fields. The elements in the fields are column matrices (1 X M) with their size consistent for given S(i).

I want to delete tails in all the 10 fields (2 data points on each side - at the beginning and the end of the vector) which, should result in the array size of (1 X M-4).

For example, the input is something like this

S(1).f1=[1,2,3,4,5,6,7,8,9,10];

S(1).f2=[2,4,6,8,10,12,14,16,18,20];

S(2).f1=[10,20,30,40,50,60,70];

S(2).f2=[150,200,250,300,350,400,450];

I want the output to be,

S(1).f1=[3,4,5,6,7,8];

S(1).f2=[6,8,10,12,14,16];

S(2).f1=[30,40,50];

S(2).f2=[250,300,350];

Answer 1

[Andrei Bobrov]

S = cell2struct(cellfun(@(x)x(3:end-2),struct2cell(S),'un',0),fieldnames(S));

[SS]

Thank you, it works well. I have an additional step here, I want to delete the fields whose size is less than 5. From the example in the question, I want to delete S(2) and all such S(i) whose length is less than 5. I have tried using this for loop,

for i=1:numel(S)

if size(S(i))<5

S(i)=[ ]

else

S(i)=newS(i)

end

end

It didn't work

[Andrei Bobrov]

S(any(cellfun(@numel,struct2cell(S)) < 5)) = []

[SS]

Thank you.

Answer 2

[Luna]

I did something like this:

newS2 = arrayfun(@(y) structfun(@(x) x(3:end-2),y,'uni',false),S)

Or:

for i = 1:numel(S)   
  newS(i) = structfun(@(x) x(3:end-2),S(i),'UniformOutput',false)    
end

[SS]

Thank you.