- Option 1: rows 1&2, then rows 3&4, then rows 5&6, and so on
- Option 2: rows 1&2, rows 2&3, rows 3&4, and so on
Creating a loop for a matrix function
2 views (last 30 days)
Katie on 27 Nov 2019
How you would write this code depends on how you want to do the function on the matrix rows:
For both cases, you can use a for loop and use the size() function to find the number of rows of the matrix you are using. size(mat,1) will give you the number of rows and size(mat,2) will give you the number of columns of the matrix "mat".
If you're looking to do option 1, you could do the following:
cnt=1;%index for a matrix "x" to store all the results in, that isn't incremented with the loop
for i=1:2:size(mat,1)%loop through the rows of the matrix at increments of 2
if i+1<=size(mat,1) %check to make sure you won't go past the last row
x(cnt)=fcn(mat(i,:),mat(i+1,:))%doing the function on the current row of the matrix and the next row
For option 2, you would make some slight changes to the above code, mainly not incrementing the for loop by 2 and not needing to check to make sure you don't try to index rows of the matrix that don't exist.
for i=1:size(mat,1)-1%loop through the rows of the matrix, using size-1 makes sure you don't go past the last row
x(i)=fcn(mat(i,:),mat(i+1,:))%doing the function on the current row of the matrix and the next row