Question about sprintf function.

Here's my syntax:

bm= input ('value');  
val = 43 ;
A = sprintf('%d',val);  
%if i declare A(1), ans is 4, which is correct. 
c=0;  
A1 = A(1) .* (bm^(c))

Why is it that if my bm = 8, A1 = 52? its like 4 * 8 = 52. i think my error here is the sprintf function.

Answer 1

[Image Analyst]

Why not just do

A1 = val;

???? bm^c is just 1, and I'm not sure if you really wanted to take the first digit of 43. If you did, you could just do

A1 = floor(A/10); % As long as A is less than 100.

instead of using sprintf. Is A really some sort of ASCII or hexadecimal number?

[Portgas Ace]

because i have to separate an array to elements for some algorithms i have to do. for example 43 i need 4 and 3 separately.

[Image Analyst]

Why not use str2double(A(1)), or str2double(A(2))? Nothing was wrong with the sprintf.

[Portgas Ace]

yup. that was what i did. btw, how do i assign values for A-F to 11-16? is the only way to do it is by if else statements?

[Image Analyst]

Now, your A is letters instead of numbers. So do this:

A = 'ABCDEF'
for k = 1 : length(A)
  theNumbers(k) = A(k) - 'A' + 11;
end
% Display:
theNumbers

In command window:

A =
ABCDEF
theNumbers =
    11    12    13    14    15    16    17    18    19    10

[Portgas Ace]

why is there 17 18 19 10? it should be up to 16 only right? since up to F only?

[Image Analyst]

Yes, you're right. It does really only go to 16. I didn't have a "clearvars" or "clear all" in there so there was left over stuff in theNumbers from prior test runs. This shows one good reason to use clear (though I know Jan doesn't like it) is to avoid goofs like this. Sorry about that.