Remove consecutive values from vector

Hey Guys,

I have this vector with increasing values (always positive) up till a certain point, after which it returns to zero again (straight line), and starts increasing again. A so called "saw" pattern. Now I am trying to determine the first indice in the vector which has a value above a certain threshold, but when I do so I get a vector with all of values above threshold.

It would be fixed if I could manage to remove the consecutive indices, and only store the first indice. I tried the following code, but this actually returns the last value of the consecutive numbers. (output is [3,7,12])

Any clue on how to change this to [1,7,10] ?

a = [1;2;3;7;10;11;12]
x = [diff(a')~=1,true];
a(x)

[Image Analyst]

Huh? How is "a" a sawtooth pattern?

[Rose]

This vector I used just as an example to illustrate what I tried to achieve...

Answer 1

[Ruger28]

a = [1;2;3;7;10;11;12];
x = diff(a);
y = vertcat(true,x~=1); % shift index down to grab first number
a(y); 

a = 1

7

10