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MathLab 2019 backward compatibility

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andrew boar
andrew boar on 4 Dec 2019
Commented: andrew boar on 5 Dec 2019
The following code compiles and runs fine in ' (R2019b) Update 1'
function approx = test3(x,N)
approx = zeros(N,1);
approx(1) = x + 1;
for i = 2:N
approx(i) = approx(i - 1) + x^i / factorial(i);
However, when I try and run it in my 2017 Uni environment, I get the following error:
Output argument "output" (and maybe others) not assigned
during call to "factorial".
Error in test3 (line 5)
approx(i) = approx(i - 1) + (x^i) / factorial(i);
Any ideas please?


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Answers (1)

J. Alex Lee
J. Alex Lee on 4 Dec 2019
is it possible that in your 2017 environment, you have inadvertently overloaded the "factorial" function?


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andrew boar
andrew boar on 4 Dec 2019
I have to say, I do have a number of years experience with many high level languages, but i am very new to MathLab. Are you saying that MathLab has access to four versions of factorial.m and does not know which one to use?
This output is from the 2017 environment.
>> which -all factorial
C:\Users\ttssb2\OneDrive - My University\MATLAB\factorial.m
C:\Program Files\MATLAB\R2017a\toolbox\distcomp\parallel\@codistributed\factorial.m % codistributed method
C:\Program Files\MATLAB\R2017a\toolbox\distcomp\gpu\@gpuArray\factorial.m % gpuArray method
C:\Program Files\MATLAB\R2017a\toolbox\symbolic\symbolic\@sym\factorial.m % sym method
C:\Program Files\MATLAB\R2017a\toolbox\matlab\specfun\factorial.m
Sean de Wolski
Sean de Wolski on 4 Dec 2019
Yes. This is the default one that ships with MATLAB that you're probably intending to call but aren't:
C:\Program Files\MATLAB\R2017a\toolbox\matlab\specfun\factorial.m
The other three in matlabroot are overloaded ones for those specific data types. The one in OneDrive is shadowing the specfun one that you're intending to call. Rename the OneDrive one to myFactorial or something to avoid the conflict.
andrew boar
andrew boar on 5 Dec 2019
Many thanks.
I can confirm this had completely resolved the issue.

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